已知一个四阶常系数齐次线性微分方程的四个线性无关的特解_(1)=(e)^3x，_(1)=(e)^3x，_(1)=(e)^3x，_(1)=(e)^3x，则这个四阶微分方程为( )。A. _(1)=(e)^3xB. _(1)=(e)^3xC. _(1)=(e)^3xD. _(1)=(e)^3x

5.曲线 -x=(e)^x(1-y) 在 x=0 处的切线方程是 __

(3)曲线 ) 与圆柱面 ^2+{y)^2=4 的交点为 () .-|||-(A) (sqrt (2),sqrt (2),pm 2) (B) (sqrt (2),sqrt (2),2)-|||-(C) (sqrt (2),sqrt (2),-2) (D) (sqrt (2),sqrt (2),pm 1)

2 1 0 0 0-|||-1 2 1 ... 0 0-|||-5.计算n阶行列式 0. 1 2 0 0-|||-: :-|||-0 0 0 2 1-|||-0 0 0 1 2

[题目]-|||-(int )_(2)^+infty dfrac (dx)((x+7)sqrt {x-2)}= __

曲线族 x^2+Cy^2=1(C 为任意常数)满足的微分方程为() A. xy+(1-x^2)y'=0 B. xy+(1+x^2)y'=0 C. xy+(1-x)y'=0 D. xy-(1-x^2)y'=0

B.一般题-|||-3.下列函数在什么情况下为无穷大?在什么情况下为无穷小?-|||-(1) =dfrac (x+2)(x-1);-|||-(2) =dfrac (x-1)({x)^2};-|||-(3) =cot x ;-|||-(4) =ln x.

.int dfrac (sqrt {1+{x)^2}+sqrt (1-{x)^2}}(sqrt {1-{x)^4}}dx.

设f(x)连续, varphi (x)=(int )_(0)^1f(xt)dt, 且 lim _(xarrow 0)dfrac (f(x))(x)=A设f(x)连续, varphi (x)=(int )_(0)^1f(xt)dt, 且 lim _(xarrow 0)dfrac (f(x))(x)=A

尖感形17个师!1~-|||-已知可微函数f(u,v)满足 dfrac (partial f(u,v))(partial u)-dfrac (partial f(u,v))(partial v)=2(u-v)(e)^-(u+v) ,且 (u,0)=(u)^2e-|||-(1)记 g(x,y)=f(x,y-x) ,求 dfrac (partial g(x,y))(partial x) ;-|||-,[ (4x-2y)-|||-(2)求f(u,v)的表达式和极值. .[ ((u)^2+(v)^2)(e)^-(u+v) ;f(0,0)=0 极小

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