[题目]一道数学竞赛试题,甲生解出它的概率为-|||-1/2, 乙生解出它的概率为 1/3, 丙生解出它的概率为 dfrac (1)(4)-|||-由甲、乙、丙三人独立解答此题只有一人解出的-|||-概率为 __

设3阶行列式|a_(11) & a_(12) & a_(13) a_(21) & a_(22) & a_(23) a_(31) & a_(32) & a_(33)|=（）.A. 2kB. 6kC. 18kD. 2k^3

A 可逆，则 ^-1|=dfrac (1)(|A|)-|||-__（）A 对B 错

考察n次独立重复试验中某个事件A恰好发生的次数，已知事件A在一次试验中发生的概率为P，则事件A至多发生一次的概率为(）。A. P(1-P)^n-1 B. np (1-p)^n-1 C. 1- (1-p)^n D. (1-p)^n + np(1-p)^n-1

3.求下列函数的微分:-|||-(1) =dfrac (1)(x)+2sqrt (x) =-|||-(2) =xsin 2x ;-|||-(3) =dfrac (x)(sqrt {{x)^2+1}} =-|||-(4) =(ln )^2(1-x) ;-|||-(5) =(x)^2(e)^2x ;-|||-(6) =(e)^-xcos (3-x) ;-|||-(7) =arcsin sqrt (1-{x)^2} :-|||-(8) =(tan )^2(1+2(x)^2) ;-|||-(9) =arctan dfrac (1-{x)^2}(1+{x)^2} =-|||-(10) =Asin (omega t+varphi )(A,omega ,varphi 是常数).

求下列函数的导数:-|||-(1) =arcsin (sin x);-|||-(2) =arctan dfrac (1+x)(1-x);-|||-(3) =ln tan dfrac (x)(2)-cos xcdot ln tan x;-|||-(4) =ln ((e)^x+sqrt (1+{e)^2x});-|||-(5) =(x)^dfrac (1{x)}(xgt 0).

根据图形规律，最适合填入问号处的图形是：?-|||-A B C DA、AB、BC、CD、D

求下列各极限:-|||-lim 1+tanx-√1+sinx

1.计算下列极限:-|||-(14) lim _(xarrow 1)(dfrac (1)(1-x)-dfrac (3)(1-{x)^3}) -

设函数f(x)和 g (x)可导,且 ^2(x)+(g)^2(x)neq 0, 试求函数 =sqrt ({f)^2(x)+(g)^2(x)} 的-|||-导数.

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