}5x_(1)+4x_(3)+2x_(4)=3x_(1)-x_(2)+2x_(3)+x_(4)=14x_(1)+x_(2)+2x_(3)=1x_(1)+x_(2)+x_(3)+x_(4)=0

$\begin{cases}5x_{1}+4x_{3}+2x_{4}=3\\x_{1}-x_{2}+2x_{3}+x_{4}=1\\4x_{1}+x_{2}+2x_{3}=1\\x_{1}+x_{2}+x_{3}+x_{4}=0\end{cases}$，则其解为（）。

A. $\begin{cases}x_{1}=1\\x_{2}=-1\\x_{3}=-1\\x_{4}=1\end{cases}$

B. $\begin{cases}x_{1}=1\\x_{2}=1\\x_{3}=-1\\x_{4}=1\end{cases}$

C. $\begin{cases}x_{1}=1\\x_{2}=1\\x_{3}=1\\x_{4}=1\end{cases}$