题目
f(t)的波形如图所示, 则F(s)=_____。1 ---|||-t-|||-(}^2[ dfrac {1)(2)-dfrac (1)(2)(e)^-2s-s(e)^-2s] 1 2A. 1 ---|||-t-|||-(}^2[ dfrac {1)(2)-dfrac (1)(2)(e)^-2s-s(e)^-2s] 1 2 B. 1 ---|||-t-|||-(}^2[ dfrac {1)(2)-dfrac (1)(2)(e)^-2s-s(e)^-2s] 1 2 C. 1 ---|||-t-|||-(}^2[ dfrac {1)(2)-dfrac (1)(2)(e)^-2s-s(e)^-2s] 1 2 D. 1 ---|||-t-|||-(}^2[ dfrac {1)(2)-dfrac (1)(2)(e)^-2s-s(e)^-2s] 1 2
f(t)的波形如图所示, 则F(s)=_____。
B.
C.
D.
题目解答
答案
ABCD
A. $\dfrac {1}{2}[ \dfrac {1}{2}-\dfrac {1}{2}{e}^{-2s}-s{e}^{-2s}] $
B. $\dfrac {1}{{s}^{2}}[ 1-{e}^{-2s}-{s}^{-2s}] $
C. $\dfrac {1}{2{S}^{2}}[ 1-{e}^{-2s}-{s}^{-2s}] $
D. $\dfrac {1}{{s}^{2}}[ \dfrac {1}{2}-\dfrac {1}{2}{e}^{-2s}-s{e}^{-2s}] $
A. $\dfrac {1}{2}[ \dfrac {1}{2}-\dfrac {1}{2}{e}^{-2s}-s{e}^{-2s}] $
B. $\dfrac {1}{{s}^{2}}[ 1-{e}^{-2s}-{s}^{-2s}] $
C. $\dfrac {1}{2{S}^{2}}[ 1-{e}^{-2s}-{s}^{-2s}] $
D. $\dfrac {1}{{s}^{2}}[ \dfrac {1}{2}-\dfrac {1}{2}{e}^{-2s}-s{e}^{-2s}] $