题目

(int )_(-1)^1(dfrac (sin x+1)(1+{x)^2}+(x)^4)dxA (int )_(-1)^1(dfrac (sin x+1)(1+{x)^2}+(x)^4)dx B (int )_(-1)^1(dfrac (sin x+1)(1+{x)^2}+(x)^4)dx C (int )_(-1)^1(dfrac (sin x+1)(1+{x)^2}+(x)^4)dxD (int )_(-1)^1(dfrac (sin x+1)(1+{x)^2}+(x)^4)dx

A   

B   

C  

D  

题目解答

答案

对原式拆分

由于是奇函数，故

因此原式积分为

故选择A