题目
(A)=0.6, (B)=0.4, (B|overline (A))=0.5,则(A)=0.6, (B)=0.4, (B|overline (A))=0.5,(A)=0.6, (B)=0.4, (B|overline (A))=0.5
,则,
题目解答
答案
解:
∵,
∴,A和B互为对立事件,
∴与
互为对立事件
∴,
∵
全集,
∴
解析
步骤 1:计算$P(\overline{A})$
$P(\overline{A}) = 1 - P(A) = 1 - 0.6 = 0.4$
步骤 2:计算$P(\overline{B})$
$P(\overline{B}) = 1 - P(B) = 1 - 0.4 = 0.6$
步骤 3:计算$P(B|\overline{A})$
已知$P(B|\overline{A}) = 0.5$
步骤 4:计算$P(\overline{A} \cap B)$
$P(\overline{A} \cap B) = P(B|\overline{A}) \cdot P(\overline{A}) = 0.5 \cdot 0.4 = 0.2$
步骤 5:计算$P(A \cap \overline{B})$
$P(A \cap \overline{B}) = P(A) - P(A \cap B)$
$P(A \cap B) = P(A) + P(B) - P(A \cup B)$
$P(A \cup B) = P(A) + P(B) - P(A \cap B)$
$P(A \cap B) = P(A) + P(B) - P(A \cup B)$
$P(A \cap B) = 0.6 + 0.4 - P(A \cup B)$
$P(A \cap B) = 1 - P(A \cup B)$
$P(A \cap \overline{B}) = P(A) - (1 - P(A \cup B))$
$P(A \cap \overline{B}) = 0.6 - (1 - P(A \cup B))$
$P(A \cap \overline{B}) = P(A \cup B) - 0.4$
步骤 6:计算$P(A|\overline{B})$
$P(A|\overline{B}) = \frac{P(A \cap \overline{B})}{P(\overline{B})} = \frac{P(A \cup B) - 0.4}{0.6}$
步骤 7:计算$P(A \cup B)$
$P(A \cup B) = P(A) + P(B) - P(A \cap B)$
$P(A \cup B) = 0.6 + 0.4 - P(A \cap B)$
$P(A \cup B) = 1 - P(A \cap B)$
$P(A \cap B) = P(A) + P(B) - P(A \cup B)$
$P(A \cap B) = 0.6 + 0.4 - P(A \cup B)$
$P(A \cap B) = 1 - P(A \cup B)$
$P(A \cup B) = 1 - P(A \cap B)$
$P(A \cup B) = 1 - (0.6 + 0.4 - P(A \cup B))$
$P(A \cup B) = 1 - 1 + P(A \cup B)$
$P(A \cup B) = P(A \cup B)$
$P(A \cup B) = 1$
$P(\overline{A}) = 1 - P(A) = 1 - 0.6 = 0.4$
步骤 2:计算$P(\overline{B})$
$P(\overline{B}) = 1 - P(B) = 1 - 0.4 = 0.6$
步骤 3:计算$P(B|\overline{A})$
已知$P(B|\overline{A}) = 0.5$
步骤 4:计算$P(\overline{A} \cap B)$
$P(\overline{A} \cap B) = P(B|\overline{A}) \cdot P(\overline{A}) = 0.5 \cdot 0.4 = 0.2$
步骤 5:计算$P(A \cap \overline{B})$
$P(A \cap \overline{B}) = P(A) - P(A \cap B)$
$P(A \cap B) = P(A) + P(B) - P(A \cup B)$
$P(A \cup B) = P(A) + P(B) - P(A \cap B)$
$P(A \cap B) = P(A) + P(B) - P(A \cup B)$
$P(A \cap B) = 0.6 + 0.4 - P(A \cup B)$
$P(A \cap B) = 1 - P(A \cup B)$
$P(A \cap \overline{B}) = P(A) - (1 - P(A \cup B))$
$P(A \cap \overline{B}) = 0.6 - (1 - P(A \cup B))$
$P(A \cap \overline{B}) = P(A \cup B) - 0.4$
步骤 6:计算$P(A|\overline{B})$
$P(A|\overline{B}) = \frac{P(A \cap \overline{B})}{P(\overline{B})} = \frac{P(A \cup B) - 0.4}{0.6}$
步骤 7:计算$P(A \cup B)$
$P(A \cup B) = P(A) + P(B) - P(A \cap B)$
$P(A \cup B) = 0.6 + 0.4 - P(A \cap B)$
$P(A \cup B) = 1 - P(A \cap B)$
$P(A \cap B) = P(A) + P(B) - P(A \cup B)$
$P(A \cap B) = 0.6 + 0.4 - P(A \cup B)$
$P(A \cap B) = 1 - P(A \cup B)$
$P(A \cup B) = 1 - P(A \cap B)$
$P(A \cup B) = 1 - (0.6 + 0.4 - P(A \cup B))$
$P(A \cup B) = 1 - 1 + P(A \cup B)$
$P(A \cup B) = P(A \cup B)$
$P(A \cup B) = 1$