用适当的变量代换将下列方程化为可分离变量的方程,然后求出通解:-|||-(1) dfrac (dy)(dx)=((x+y))^2;-|||-(2) dfrac (dy)(dx)=dfrac (1)(x-y)+1;-|||-(3) '+y=y(ln x+ln y);-|||-(4) '=(y)^2+2(sin x-1)y+(sin )^2x-2sin x-cos x +1;-|||-(5) (xy+1)dx+x(1+xy+(x)^2(y)^2)dy=0.