题目
曲面 x cos z + y cos x - (pi)/(2) z = (pi)/(2) 在点 ((pi)/(2), 1 - (pi)/(2), 0 ) 处的切平面方程为A. x - y = pi - 1B. x - z = (pi)/(2)C. x - z = pi - 1D. x - y = (pi)/(2)
曲面 $x \cos z + y \cos x - \frac{\pi}{2} z = \frac{\pi}{2}$ 在点 $\left(\frac{\pi}{2}, 1 - \frac{\pi}{2}, 0 \right)$ 处的切平面方程为
A. $x - y = \pi - 1$
B. $x - z = \frac{\pi}{2}$
C. $x - z = \pi - 1$
D. $x - y = \frac{\pi}{2}$
题目解答
答案
B. $x - z = \frac{\pi}{2}$