题目
函数z=ln(1+x+2y)在点(1,1)处的全微分为A. 2ln2, (dx + dy)B. (1)/(4), (dx + dy)C. (1)/(4), dx + (1)/(2), dyD. (1)/(2), dx + (1)/(4), dy
函数$z=\ln(1+x+2y)$在点$(1,1)$处的全微分为
A. $2\ln2\, (dx + dy)$
B. $\frac{1}{4}\, (dx + dy)$
C. $\frac{1}{4}\, dx + \frac{1}{2}\, dy$
D. $\frac{1}{2}\, dx + \frac{1}{4}\, dy$
题目解答
答案
C. $\frac{1}{4}\, dx + \frac{1}{2}\, dy$