题目
已知级数sum_(n=1)^infty(1)/(n^2)=(pi^2)/(6)，则级数sum_(n=1)^infty(1)/((2n-1)^2)的和为A. (pi^2)/(2)B. (pi^2)/(6)C. (pi^2)/(4)D. (pi^2)/(8)
已知级数$\sum_{n=1}^{\infty}\frac{1}{n^2}=\frac{\pi^2}{6}$，则级数$\sum_{n=1}^{\infty}\frac{1}{(2n-1)^2}$的和为
A. $\frac{\pi^2}{2}$
B. $\frac{\pi^2}{6}$
C. $\frac{\pi^2}{4}$
D. $\frac{\pi^2}{8}$
题目解答
答案
D. $\frac{\pi^2}{8}$