1.求下列曲线的弧长:-|||-(1) =(x)^3/2, (2)、 sqrt (x)+sqrt (y)=1;-|||-(3) =a(cos )^3t, =a(sin )^3t(agt 0) leqslant tleqslant 2pi ;-|||-(4) =a(cos t+tsin t), =a(sin t-tcos t)(agt 0) leqslant tleqslant 2pi ;-|||-(5) =a(sin )^3dfrac (theta )(3)(agt 0,0leqslant theta leqslant 3pi ;-|||-(6) =alpha theta (agt 0) leqslant theta leqslant 2pi .leqslant xleqslant 4;1.求下列曲线的弧长:-|||-(1) =(x)^3/2, (2)、 sqrt (x)+sqrt (y)=1;-|||-(3) =a(cos )^3t, =a(sin )^3t(agt 0) leqslant tleqslant 2pi ;-|||-(4) =a(cos t+tsin t), =a(sin t-tcos t)(agt 0) leqslant tleqslant 2pi ;-|||-(5) =a(sin )^3dfrac (theta )(3)(agt 0,0leqslant theta leqslant 3pi ;-|||-(6) =alpha theta (agt 0) leqslant theta leqslant 2pi .leqslant xleqslant 4;