题目
下列哪个函数不能作为调和函数?A. log(x^2 + y^2)B. x^2 - y^2C. x^3 - 3xy^2D. (1)/(x^2 + y^2)
下列哪个函数不能作为调和函数? A. $\log(x^2 + y^2)$ B. $x^2 - y^2$ C. $x^3 - 3xy^2$ D. $\frac{1}{x^2 + y^2}$
题目解答
答案
**答案:D**
**解析:**
调和函数满足拉普拉斯方程 $\nabla^2 u = \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0$。
- **选项A:** $\theta = \log(x^2 + y^2)$
\[
\nabla^2 \theta = \frac{2y^2 - 2x^2}{(x^2 + y^2)^2} + \frac{2x^2 - 2y^2}{(x^2 + y^2)^2} = 0
\]
满足拉普拉斯方程,是调和函数。
- **选项B:** $u = x^2 - y^2$
\[
\nabla^2 u = 2 + (-2) = 0
\]
满足拉普拉斯方程,是调和函数。
- **选项C:** $v = x^3 - 3xy^2$
\[
\nabla^2 v = 6x + (-6x) = 0
\]
满足拉普拉斯方程,是调和函数。
- **选项D:** $w = \frac{1}{x^2 + y^2}$
\[
\nabla^2 w = \frac{6x^2 - 2y^2}{(x^2 + y^2)^3} + \frac{-2x^2 + 6y^2}{(x^2 + y^2)^3} = \frac{4(x^2 + y^2)}{(x^2 + y^2)^3} = \frac{4}{(x^2 + y^2)^2} \neq 0
\]
不满足拉普拉斯方程,不是调和函数。
**结论:** 选项D不能作为调和函数。
$\boxed{D}$
解析
调和函数的定义是满足拉普拉斯方程$\nabla^2 u = \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0$的函数。本题需要逐一验证四个选项是否满足该方程。关键在于正确计算二阶偏导数并求和,尤其注意选项D的计算容易出错。
选项A:$\log(x^2 + y^2)$
- 一阶偏导:$\frac{\partial u}{\partial x} = \frac{2x}{x^2 + y^2}$,$\frac{\partial u}{\partial y} = \frac{2y}{x^2 + y^2}$。
- 二阶偏导:
- $\frac{\partial^2 u}{\partial x^2} = \frac{2(x^2 + y^2) - 4x^2}{(x^2 + y^2)^2} = \frac{2y^2 - 2x^2}{(x^2 + y^2)^2}$,
- $\frac{\partial^2 u}{\partial y^2} = \frac{2(x^2 + y^2) - 4y^2}{(x^2 + y^2)^2} = \frac{2x^2 - 2y^2}{(x^2 + y^2)^2}$。
- 求和:$\nabla^2 u = 0$,满足调和函数。
选项B:$x^2 - y^2$
- 二阶偏导:
- $\frac{\partial^2 u}{\partial x^2} = 2$,
- $\frac{\partial^2 u}{\partial y^2} = -2$。
- 求和:$\nabla^2 u = 2 + (-2) = 0$,满足调和函数。
选项C:$x^3 - 3xy^2$
- 二阶偏导:
- $\frac{\partial^2 u}{\partial x^2} = 6x$,
- $\frac{\partial^2 u}{\partial y^2} = -6x$。
- 求和:$\nabla^2 u = 6x + (-6x) = 0$,满足调和函数。
选项D:$\frac{1}{x^2 + y^2}$
- 一阶偏导:$\frac{\partial w}{\partial x} = \frac{-2x}{(x^2 + y^2)^2}$,$\frac{\partial w}{\partial y} = \frac{-2y}{(x^2 + y^2)^2}$。
- 二阶偏导:
- $\frac{\partial^2 w}{\partial x^2} = \frac{-2(x^2 + y^2)^2 + 8x^2(x^2 + y^2)}{(x^2 + y^2)^4} = \frac{6x^2 - 2y^2}{(x^2 + y^2)^3}$,
- $\frac{\partial^2 w}{\partial y^2} = \frac{-2(x^2 + y^2)^2 + 8y^2(x^2 + y^2)}{(x^2 + y^2)^4} = \frac{-2x^2 + 6y^2}{(x^2 + y^2)^3}$。
- 求和:$\nabla^2 w = \frac{4(x^2 + y^2)}{(x^2 + y^2)^3} = \frac{4}{(x^2 + y^2)^2} \neq 0$,不满足调和函数。