[题目]-|||-以初速度v0竖直向上抛出一质量为m的小球,-|||-小球除受重力外,还受一个大小为 kmv2 的粘滞-|||-阻力,求小球上升的最大高度-|||-A =dfrac (1)(2k)ln (dfrac (q+k{{v)_(0)}^2}(g))-|||-B .=dfrac (1)(k)ln (dfrac (g+k{{v)_(0)}^2}(g))-|||-C =dfrac (1)(2k)ln (dfrac (g+2k{{v)_(0)}^2}(g))-|||-D =dfrac (1)(k)ln (dfrac (g+2k{{v)_(0)}^2}(g))