题目2.求下列齐次方程满足所给初值条件的特解:-|||-(1) ((y)^2-3(x)^2)dy+2xydx=0 |x=0=1;-|||-(2) '=dfrac (x)(y)+dfrac (y)(x),y|,x=1=2;-|||-(3) ((x)^2+2xy-(y)^2)dx+((y)^2+2xy-(x)^2)dy=0, |x=1=1.题目解答答案