题目
设 I = int_(0)^2 dy int_(y^2)^2y f(x, y)dx，交换积分次序后，则 I = ( )A. I = int_(0)^2 dx int_(y^2)^2y f(x, y)dyB. I = int_(0)^4 dx int_(x/2)^sqrt(x) f(x, y)dyC. I = int_(0)^2 dx int_(2x)^sqrt(x) f(x, y)dyD. I = int_(0)^1 dx int_(x)^sqrt(x) f(x, y)dy
设 $I = \int_{0}^{2} dy \int_{y^2}^{2y} f(x, y)dx$，交换积分次序后，则 $I = (\quad)$
A. $I = \int_{0}^{2} dx \int_{y^2}^{2y} f(x, y)dy$
B. $I = \int_{0}^{4} dx \int_{x/2}^{\sqrt{x}} f(x, y)dy$
C. $I = \int_{0}^{2} dx \int_{2x}^{\sqrt{x}} f(x, y)dy$
D. $I = \int_{0}^{1} dx \int_{x}^{\sqrt{x}} f(x, y)dy$
题目解答
答案
B. $I = \int_{0}^{4} dx \int_{x/2}^{\sqrt{x}} f(x, y)dy$