已知标量场u(x,y,z)=x^3y-y^2z+2xz^2,矢量场vec(H)(x,y,z)=xyvec(e)_(x)+yzvec(e)_(y)+zxvec(e)_(z),试完成以下运算:1).计算标量场u的梯度∇u;2).计算矢量场vec(H)的散度∇·vec(H);3).计算∇·(∇u)。
题目解答
答案
-
梯度计算
$ u(x, y, z) = x^3y - y^2z + 2xz^2 $
$\nabla u = \left( \frac{\partial u}{\partial x}, \frac{\partial u}{\partial y}, \frac{\partial u}{\partial z} \right) = (3x^2y + 2z^2, x^3 - 2yz, -y^2 + 4xz)$
答案:
$\boxed{(3x^2y + 2z^2) \vec{e}_x + (x^3 - 2yz) \vec{e}_y + (-y^2 + 4xz) \vec{e}_z}$ -
散度计算
$ \vec{H}(x, y, z) = xy \vec{e}_x + yz \vec{e}_y + zx \vec{e}_z $
$\nabla \cdot \vec{H} = \frac{\partial H_x}{\partial x} + \frac{\partial H_y}{\partial y} + \frac{\partial H_z}{\partial z} = y + z + x = x + y + z$
答案:
$\boxed{x + y + z}$ -
拉普拉斯算子计算
$\nabla \cdot (\nabla u) = \nabla^2 u = \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} + \frac{\partial^2 u}{\partial z^2} = 6xy - 2z + 4x$
答案:
$\boxed{6xy - 2z + 4x}$