题目
化 tan dfrac (pi -C)(2)=-pi `D =dfrac (E+C)(2)=cotdfrac (4)(2)-|||-6三年 therefore dfrac (pi )(4)=dfrac (1)(3) _(0)=dfrac (1)(3) ()-|||-(A) dfrac (dfrac {sqrt {3)}(3)} 18 -dfrac (2sqrt {3)}(3)-|||-`c} dfrac (1)(3) (D -dfrac (1)(3)-|||-7.已 sin (y=-a)=dfrac (1)(3) .because 2+2+1dfrac (11pi )(2)=(a)_(1) 方于1-|||-(A) -dfrac (1)(2) IB dfrac (1)(2)-|||-(C) dfrac (sqrt {y)}(2) 10 -dfrac (sqrt {3)}(2)-|||-B.已 |tan (pi -alpha )=-2sin (dfrac (pi )(2)+alpha ) in acown n等于-|||-()-|||-(A. dfrac (2)(5) tB. -dfrac (2)(5)-|||-(c) dfrac (2)(5) 或 -dfrac (2)(5) (D) -dfrac (1)(5)-|||-9.+ ow(π+2) 化为,下个键扇的三你面效办 ()-|||-(Ale)^2 (B) -ros2-|||-(c -cot (-2) (D cos(π-2)-|||-10已厘 tan (pi +{tan )^2)=3, 则 dfrac (sin (alpha -3pi )tan (pi -a))(sin (-alpha )-cos (pi +alpha ))-|||-km(-a)-cos(π+α)-|||-11.已知A=+in(k=+a) tolesta ∠t∈Z1,则A-|||-,ina pm-|||-的饭!或电约来台÷ ()-|||-(A) https:/img.zuoyebang.cc/zyb_63b1897d911805b7423a63bb07ba5199.jpg,-1,2,-21 1B) ... 11-|||-tc: ... ... 2 ID |1,-1,0,2,-1-|||-12.当出下列三角函数,其一等号治员的是 ()-|||-1A !-1000=1-|||-(B =-2=(10)-|||-C Cun(-10)-|||-(D)-10/(mx)/(x^2s-|||-tan --|||-二、填空题[亲大共4小兰,每小题5分,共20分)-|||-sin (-dfrac (1pi )(3))= __-|||-(cos )^2+(3)^ncdot (cos )^3(45)^circ +(cos )^circ (45)^circ +(cos )^3(45)^circ cdot (cos )^2(45)^circ =(10)^circ -|||-__-|||-15.已知 (x)= )+f(dfrac {11)(6))=-|||-__-|||-16.已知锐角a终边上一点 [ 2sin 3,-2cos (3),-|||-吗们a的圆度数为 __

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答案
ADCBD DA