题目
微分方程 (x^2-1)dy + (2xy - cos x)dx = 0 满足 y|_(x=0) = 1 的特解是(）.A. y = (sin x - 1)/(x^2 - 1)B. y = (cos x)/(1 + x^2)C. y = (sin x + 1)/(x^2 + 1)D. y = (cos x)/(1 - x^2)
微分方程 $(x^2-1)dy + (2xy - \cos x)dx = 0$ 满足 $y|_{x=0} = 1$ 的特解是(）.
A. $y = \frac{\sin x - 1}{x^2 - 1}$
B. $y = \frac{\cos x}{1 + x^2}$
C. $y = \frac{\sin x + 1}{x^2 + 1}$
D. $y = \frac{\cos x}{1 - x^2}$
题目解答
答案
A. $y = \frac{\sin x - 1}{x^2 - 1}$