题目
(2) 求函数 z = x ^ ( 3 ) + y ^ ( 3 ) - 3 x ^ ( 2 ) - 3 y ^ ( 2 ) 的极值.
(2) 求函数 $z = x ^ { 3 } + y ^ { 3 } - 3 x ^ { 2 } - 3 y ^ { 2 }$ 的极值.
题目解答
答案
求偏导数:
\[
\frac{\partial z}{\partial x} = 3x^2 - 6x, \quad \frac{\partial z}{\partial y} = 3y^2 - 6y
\]
解得驻点:
\[
(0,0), (0,2), (2,0), (2,2)
\]
计算二阶偏导数:
\[
\frac{\partial^2 z}{\partial x^2} = 6x - 6, \quad \frac{\partial^2 z}{\partial y^2} = 6y - 6, \quad \frac{\partial^2 z}{\partial x \partial y} = 0
\]
判别式 $D = (6x-6)(6y-6)$:
- 对于 $(0,0)$:$D = 36 > 0$,$\frac{\partial^2 z}{\partial x^2} = -6 < 0$,极大值点
- 对于 $(0,2)$ 和 $(2,0)$:$D = -36 < 0$,非极值点
- 对于 $(2,2)$:$D = 36 > 0$,$\frac{\partial^2 z}{\partial x^2} = 6 > 0$,极小值点
计算极值:
\[
z(0,0) = 0, \quad z(2,2) = -8
\]
**答案:**
极大值:$z(0,0) = 0$
极小值:$z(2,2) = -8$