题目

以点P(1,2,3)为球心，半径为4的球面方程为:A. (x-1)^2 + (y-2)^2 + (z-3)^2 = 16B. (x-1)^2 + (y-2)^2 + (z-3)^2 = 4C. (x+1)^2 + (y+2)^2 + (z+3)^2 = 16D. (x+1)^2 + (y+2)^2 + (z+3)^2 = 4

以点P(1,2,3)为球心，半径为4的球面方程为:

A. $(x-1)^2 + (y-2)^2 + (z-3)^2 = 16$

B. $(x-1)^2 + (y-2)^2 + (z-3)^2 = 4$

C. $(x+1)^2 + (y+2)^2 + (z+3)^2 = 16$

D. $(x+1)^2 + (y+2)^2 + (z+3)^2 = 4$

题目解答

答案

A. $(x-1)^2 + (y-2)^2 + (z-3)^2 = 16$