2.求下列微分方程满足初始条件的特解:-|||-(1) (1+(e)^x)yy'=(e)^x |x=0=1;-|||-(2) +(1+(x)^2)dy=0 |x=1=3;-|||-(3) dfrac (dy)(dx)-sin x(1+cos x)=0, |x=dfrac (pi )(4)=-1;-|||-(4) '+1=4(e)^-y |x=-2=0;-|||-(5) dfrac (dy)(dx)+dfrac (y)(x)=dfrac (sin x)(x),y|x-dfrac (pi )(2)=2;-|||-(6) cos xy'+ysin x=1 |x=0=0;-|||-(7) '+y-(e)^x=0,y|x=1=3e;-|||-(8) '+3xy=x, |x=0=-dfrac (1)(2);-|||-(9) ^n-4(y)^i+3y=0 (0)=6, '(0)=10;-|||-(10) ^n+4(y)^i+29y=0 (0)=0, '(0)=15;-|||-(11) (y)^n+4(y)^n+y=0 (0)=2, '(0)=0;-|||-(12) dfrac ({d)^2s}(d{t)^2}+2dfrac (ds)(dt)+5s=0 (0)=5, '(0)=-5; 2.求下列微分方程满足初始条件的特解:-|||-(1) (1+(e)^x)yy'=(e)^x |x=0=1;-|||-(2) +(1+(x)^2)dy=0 |x=1=3;-|||-(3) dfrac (dy)(dx)-sin x(1+cos x)=0, |x=dfrac (pi )(4)=-1;-|||-(4) '+1=4(e)^-y |x=-2=0;-|||-(5) dfrac (dy)(dx)+dfrac (y)(x)=dfrac (sin x)(x),y|x-dfrac (pi )(2)=2;-|||-(6) cos xy'+ysin x=1 |x=0=0;-|||-(7) '+y-(e)^x=0,y|x=1=3e;-|||-(8) '+3xy=x, |x=0=-dfrac (1)(2);-|||-(9) ^n-4(y)^i+3y=0 (0)=6, '(0)=10;-|||-(10) ^n+4(y)^i+29y=0 (0)=0, '(0)=15;-|||-(11) (y)^n+4(y)^n+y=0 (0)=2, '(0)=0;-|||-(12) dfrac ({d)^2s}(d{t)^2}+2dfrac (ds)(dt)+5s=0 (0)=5, '(0)=-5;