题目
设 z(x, y) 是由 z + ln z - int_(y)^x e^-t^2 dt = 0 确定的隐函数，则 (partial z)/(partial y) = ( ).A. -(1)/(z) - e^-y^2B. -(1+z)/(ze^-y^2)C. -(ze^-y^2)/(1+z)D. (ze^-y^2)/(1+z)
设 $z(x, y)$ 是由 $z + \ln z - \int_{y}^{x} e^{-t^2} dt = 0$ 确定的隐函数，则 $\frac{\partial z}{\partial y} = (\quad)$.
A. $-\frac{1}{z} - e^{-y^2}$
B. $-\frac{1+z}{ze^{-y^2}}$
C. $-\frac{ze^{-y^2}}{1+z}$
D. $\frac{ze^{-y^2}}{1+z}$
题目解答
答案
C. $-\frac{ze^{-y^2}}{1+z}$