"按有效数字运算规则,算出下列各式之值(写出中间运算步骤).(1)dfrac (100.0times ( {5.6+4.412) )} ( ( {78.00-77.0) )times 10.000}+110.0(2)dfrac (101.0times ( {4.6+4.402) )} ( ( {89.00-88.0) )times 10.000}+210.00(3)dfrac (21.00) (40.00-33.0)(4)dfrac ( ( {26.10-14.1) )times 30.00} ( ( {204-30) )times ( (1.00+0.001) )}"
按有效数字运算规则,算出下列各式之值(写出中间运算步骤).
(1)$\dfrac {100.0\times \left ( {5.6+4.412} \right )} {\left ( {78.00-77.0} \right )\times 10.000}+110.0$
(2)$\dfrac {101.0\times \left ( {4.6+4.402} \right )} {\left ( {89.00-88.0} \right )\times 10.000}+210.00$
(3)$\dfrac {21.00} {40.00-33.0}$
(4)$\dfrac {\left ( {26.10-14.1} \right )\times 30.00} {\left ( {204-30} \right )\times \left ( {1.00+0.001} \right )}$
"题目解答
答案
【答案】
(1)$210.12$;(2)$300.9202$;(3)3;(4)$\dfrac {60000} {29029}$.
【解析】
(1)
$\dfrac {100.0\times \left ( {5.6+4.412} \right )} {\left ( {78.00-77.0} \right )\times 10.000}+110.0$
$=\dfrac {100.0\times 10.012} {1.00\times 10.000}+110.0$
$=\dfrac {1001.2} {10}+110.0$
$=100.12+110.0$
$=210.12$
(2)
$\dfrac {101.0\times \left ( {4.6+4.402} \right )} {\left ( {89.00-88.0} \right )\times 10.000}+210.00$
$=\dfrac {101.0\times 9.002} {1.0\times 10.000}+210.00$
$=\dfrac {909.202} {10}+210.00$
$=90.9202+210.00$
$=300.9202$
(3)
$\dfrac {21.00} {40.00-33.0}$
$=\dfrac {21.00} {7.00}$
$=3$
(4)
$\dfrac {\left ( {26.10-14.1} \right )\times 30.00} {\left ( {204-30} \right )\times \left ( {1.00+0.001} \right )}$
$=\dfrac {12.00\times 30.00} {174\times 1.001}$
$=\dfrac {360.00} {174.174}$
$=\dfrac {60000} {29029}$
"解析
先计算括号内的加法和减法,然后进行乘除运算,最后加上110.0。
步骤 2:计算(2)式
先计算括号内的加法和减法,然后进行乘除运算,最后加上210.00。
步骤 3:计算(3)式
先计算分母的减法,然后进行除法运算。
步骤 4:计算(4)式
先计算括号内的加法和减法,然后进行乘除运算。