设f(x)在[0,1]上连续,在(0,1)内二阶可导,且-|||-f(0)=f(1)=0 , ''(x)lt 0(xin (0,1)).-|||-若f(x)在[0,1]上的最大值为 gt 0, 求证:对任意的自然数n,-|||-(1)存在惟一的 _(n)in (0,1), 使得 '((x)_(n))=dfrac (M)(n);-|||-(2)极限limxn存在,并且 (ln (x)_(n))=M.