题目
曲面z=(x)^2-2(y)^2-1在点(1,1,-2)处的切平面方程为( )A.2x-4y-z=0B.x+y+z=0C.x-y-z=0D.2x+4y+z=0
曲面$z={x}^{2}-2{y}^{2}-1$在点$(1,1,-2)$处的切平面方程为( )
A.$2x-4y-z=0$
B.$x+y+z=0$
C.$x-y-z=0$
D.$2x+4y+z=0$
题目解答
答案
曲面$z={x}^{2}-2{y}^{2}-1$在点$(1,1,-2)$处的切平面方程为( )
A.$2x-4y-z=0$
B.$x+y+z=0$
C.$x-y-z=0$
D.$2x+4y+z=0$