题目
若 y_1, y_2 是方程 y' + P(x)y = Q(x) (Q(x)neq 0)的两个特解，要使 alpha y_1 + beta y_2 也是解，则 alpha 与 beta 应满足的关系是A. alpha + beta = (1)/(2)B. alpha + beta = 1C. alpha beta = 0D. alpha = beta = (1)/(2)
若 $y_1, y_2$ 是方程 $y' + P(x)y = Q(x)$ ($Q(x)\neq 0$)的两个特解，要使 $\alpha y_1 + \beta y_2$ 也是解，则 $\alpha$ 与 $\beta$ 应满足的关系是
A. $\alpha + \beta = \frac{1}{2}$
B. $\alpha + \beta = 1$
C. $\alpha \beta = 0$
D. $\alpha = \beta = \frac{1}{2}$
题目解答
答案
B. $\alpha + \beta = 1$