2球形电容器两同心金属球面的半径分别为R1,R2,各自带有等量异号电荷 +a-0, 置于真空当中,则[]-|||-R1-|||-R 2 +Q -Q-|||-(6.0分)-|||-两球面间的电势差为 dfrac (1)(4pi {varepsilon )_(0)}(dfrac (Q)({R)_(1)}-dfrac (2Q)({R)_(2)})-|||-B、-|||-两球面间的电势差为 dfrac (Q)(4pi {varepsilon )_(0)}(dfrac (1)({R)_(1)}-dfrac (1)({R)_(2)})-|||-(-|||-该电容器的电容为 pi (varepsilon )_(0)(dfrac ({R)_(1)(R)_(2)}({R)_(2)-(R)_(1)})-|||-V 两球面间的电场强度为 dfrac (Q)(4pi {varepsilon )_(0)(r)^2}