有两个电荷都是 +9 的点电荷,相距为2a。今以左边的点电荷-|||-所在处为球心,以a为半径作一球形高斯面。在球面上取两块-|||-相等的小面积S1和S2,其位置如图所示。设通过S1和S2的电场-|||-强度通量分别为1和2,通过整个球面的电场强度通量为s,-|||-则 ()-|||-S1、 q S2-|||-0 2a-|||-→x-|||-A.. https:/img.zuoyebang.cc/zyb_2a06c0f6080dd04114583a615e8e8581.jpggt 2 , (varphi )_(s)=dfrac (q)({varepsilon )_(0)} B. https:/img.zuoyebang.cc/zyb_2a06c0f6080dd04114583a615e8e8581.jpglt 2 , (varphi )_(s)=dfrac (2q)({s)_(0)}-|||-C. 1=2 , (varphi )_(s)=dfrac (q)({varepsilon )_(0)} D. https:/img.zuoyebang.cc/zyb_2a06c0f6080dd04114583a615e8e8581.jpglt 2 , (varphi )_(s)=dfrac (q)({varepsilon )_(0)}