题目
空间曲线 Y: x = 1 + t , y = 1 + t^2, z = -t + t^2在 (1,1,0)点处的切线方程为()。A. x - z - 1 = 0 B. (x-1)/(1)= (z)/(-1) C. (x-1)/(1)= (y-1)/(0)= (z)/(-1) D. (x-1)/(1)= (y-1)/(1)= (z)/(-1)
空间曲线 $Y: x = 1\ \ + t $, $y = 1\ \ + t^2$, $z = -t + t^2$在 $(1,1,0)$点处的切线方程为()。
A. $x - z - 1 = 0 $
B. $$ $\frac {x-1}{1}= \frac {z}{-1}$ $$
C. $$ $\frac {x-1}{1}= \frac {y-1}{0}= \frac {z}{-1}$ $$
D. $$ $\frac {x-1}{1}= \frac {y-1}{1}= \frac {z}{-1}$ $$
题目解答
答案
C. $$ $\frac {x-1}{1}= \frac {y-1}{0}= \frac {z}{-1}$ $$