在静电场中下面正确的表达式是A. nabla cdot E = (1)/(varepsilon_0) int_(v) rho , dvB. oint_(l) E cdot dl = qC. nabla times E = 0D. oint_(s) E cdot dl = (1)/(varepsilon_0) int_(v) rho , dv

A. $\nabla \cdot E = \frac{1}{\varepsilon_0} \int_{v} \rho \, dv$

B. $\oint_{l} E \cdot dl = q$

C. $\nabla \times E = 0$

D. $\oint_{s} E \cdot dl = \frac{1}{\varepsilon_0} \int_{v} \rho \, dv$