题目
如图所示 球形电容器两同心金属球面的半径分别为R1,R2,各自带有等量异号电荷 +0.. 置于真空当中,则( )-|||-R-|||-R 2 +9 Q-|||-(6.0分)-|||-该电容器的电容为 pi (varepsilon )_(0)cdot (dfrac ({R)_(1)(R)_(2)}({R)_(2)-(R)_(1)})-|||-两球面间的电势差为 dfrac (1)(4pi {varepsilon )_(0)}(dfrac (Q)({R)_(1)}-dfrac (2Q)({R)_(2)})-|||-两球面间的电势差为 dfrac (Q)(4pi {varepsilon )_(0)}(dfrac (1)({R)_(1)}-dfrac (1)({R)_(2)})-|||-两球面间的电场强度为 dfrac (partial z)(4m{varepsilon )_(n)(r)^2}-|||-D
如图所示

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答案
