题目
1mol刚性双原子分子理想气体从状态a沿如图所示的直线过程变化到状态b,关于这个过程说法正确的是-|||-P-|||-_(2) b-|||-_(1) a-|||-o v V2 v-|||-__-|||-(10.0分)-|||-A、 气体内能的增量-|||-Delta E=dfrac (5)(2)((P)_(2)(V)_(2)-(P)_(1)(V)_(1))-|||-B 气体对外界做的功-|||-=dfrac (1)(2)((P)_(1)+(P)_(2))((V)_(2)-(V)_(1))-|||-C. 气体内能的增量-|||-Delta E=dfrac (7)(2)((P)_(2)(V)_(2)-(P)_(1)(V)_(1))-|||-D.气体吸收的热量-|||-=dfrac (1)(2)((P)_(1)(V)_(2)-(P)_(2)(V)_(1))+3((P)_(2)(V)_(2)-(P)_(1)(V)_(1))

题目解答
答案
