题目
球面x^2+y^2+z^2=3与平面x+y+z=1的交线在xoy坐标面上的投影方程为()A. x^2+y^2=3B. x^2+xy+y^2-x-y=1C. {x^2+y^2=3 z=0.
球面$x^{2}+y^{2}+z^{2}=3$与平面$x+y+z=1$的交线在$xoy$坐标面上的投影方程为()
A. $x^{2}+y^{2}=3$
B. $x^{2}+xy+y^{2}-x-y=1$
C. $\left\{\begin{array}{l}x^{2}+y^{2}=3 \\ z=0\end{array}\right.$
D. $\left\{\begin{array}{l}x^{2}+xy+y^{2}-x-y=1 \\ z=0\end{array}\right.$
题目解答
答案
D. $\left\{\begin{array}{l}x^{2}+xy+y^{2}-x-y=1 \\ z=0\end{array}\right.$