题目
15.简答题-|||-sim N((3,2)^2)-|||-设随机变量-|||-①求 (2lt Xleqslant 4) ;②求 (|X-3|gt 4) ;③确定c-|||-= =-|||-使得 (Xgt c)=P(Xlt c) ._-|||-.(0.5)=0.6915 ,(2)=0.9772 ,-|||-()
题目解答
答案
①$P(2②$P(|X-3|\leqslant 4)=P(-1\leqslant X-3\leqslant 4)=\Phi (4)-\Phi (-1)=0.9772-0.1587=0.8185$③$P(X\gt c)=P(X\lt c)$ 即 $c=0$①$0.4772$②$0.8185$③$c=0$
①$0.4772$②$0.8185$③$c=0$
①$0.4772$②$0.8185$③$c=0$