题目
4. (5.0分) 12. sin(1+2i)=（ ）A. (1)/(2)(e^2-e^-2)sin1+(i)/(2)(e^2+e^-2)cos1B. (1)/(2)(e^2-e^-2)cos1+(i)/(2)(e^2+e^-2)sin1C. (1)/(2)(e^2+e^-2)cos1+(i)/(2)(e^2-e^-2)sin1D. (1)/(2)(e^2+e^-2)sin1+(i)/(2)(e^2-e^-2)cos1
4. (5.0分) 12. $\sin(1+2i)$=（ ）
A. $\frac{1}{2}(e^{2}-e^{-2})\sin1+\frac{i}{2}(e^{2}+e^{-2})\cos1$
B. $\frac{1}{2}(e^{2}-e^{-2})\cos1+\frac{i}{2}(e^{2}+e^{-2})\sin1$
C. $\frac{1}{2}(e^{2}+e^{-2})\cos1+\frac{i}{2}(e^{2}-e^{-2})\sin1$
D. $\frac{1}{2}(e^{2}+e^{-2})\sin1+\frac{i}{2}(e^{2}-e^{-2})\cos1$
题目解答
答案
D. $\frac{1}{2}(e^{2}+e^{-2})\sin1+\frac{i}{2}(e^{2}-e^{-2})\cos1$