题目
复数 (1-i)/(2) - (3i)/(1-i) 的三角式为（）A. 2sqrt(2)(cos (1)/(4)pi + isin (1)/(4)pi)B. 2sqrt(2)(cos (-1)/(4)pi + isin (-1)/(4)pi)C. sqrt(2)(cos (3)/(4)pi - isin (3)/(4)pi)D. sqrt(2)(cos (3)/(4)pi + isin (3)/(4)pi)
复数 $\frac{1-i}{2} - \frac{3i}{1-i}$ 的三角式为（）
A. $2\sqrt{2}\left(\cos \frac{1}{4}\pi + i\sin \frac{1}{4}\pi\right)$
B. $2\sqrt{2}\left(\cos \frac{-1}{4}\pi + i\sin \frac{-1}{4}\pi\right)$
C. $\sqrt{2}\left(\cos \frac{3}{4}\pi - i\sin \frac{3}{4}\pi\right)$
D. $\sqrt{2}\left(\cos \frac{3}{4}\pi + i\sin \frac{3}{4}\pi\right)$
题目解答
答案
B. $2\sqrt{2}\left(\cos \frac{-1}{4}\pi + i\sin \frac{-1}{4}\pi\right)$