题目
周期信号傅里叶级数三角函数展开式计算的系数是（ ）。A. b_n = (2)/(T) int_(-T/2)^T/2 f_T(t) sin n omega_0 t , dtB. a_n = (2)/(T) int_(-T/2)^T/2 f_T(t) cos n omega_0 t , dtC. F_n = (1)/(T) int_(-(T)/(2))^(T)/(2) f_T(t) e^-j n omega_0 t , dtD. a_0 = (1)/(T) int_(-T/2)^T/2 f_T(t) , dt
周期信号傅里叶级数三角函数展开式计算的系数是（ ）。
A. $b_n = \frac{2}{T} \int_{-T/2}^{T/2} f_T(t) \sin n \omega_0 t \, dt$
B. $a_n = \frac{2}{T} \int_{-T/2}^{T/2} f_T(t) \cos n \omega_0 t \, dt$
C. $F_n = \frac{1}{T} \int_{-\frac{T}{2}}^{\frac{T}{2}} f_T(t) e^{-j n \omega_0 t} \, dt$
D. $a_0 = \frac{1}{T} \int_{-T/2}^{T/2} f_T(t) \, dt$
题目解答
答案
AB
A. $b_n = \frac{2}{T} \int_{-T/2}^{T/2} f_T(t) \sin n \omega_0 t \, dt$
B. $a_n = \frac{2}{T} \int_{-T/2}^{T/2} f_T(t) \cos n \omega_0 t \, dt$
A. $b_n = \frac{2}{T} \int_{-T/2}^{T/2} f_T(t) \sin n \omega_0 t \, dt$
B. $a_n = \frac{2}{T} \int_{-T/2}^{T/2} f_T(t) \cos n \omega_0 t \, dt$