题目已知 N_(1) = 3 + j4，N_(2) = -sqrt(3) - j，计算 N_(1) cdot N_(2) = 10 angle -96.9^circA. 对B. 错已知 $N_{1} = 3 + j4$，$N_{2} = -\sqrt{3} - j$，计算 $N_{1} \cdot N_{2} = 10 \angle -96.9^\circ$A. 对B. 错题目解答答案A. 对