1.判断正误.-|||-(1)设 lim (z)_(n)=(z)_(0), 若对任意n,f在zn不可导,则了在z0不解析. ()-|||-(2)设 lim (n)_(n)=(z)_(0), 若f在z0连续,且对任意n,f在zn解析则f在z0解析.-|||-()-|||-(3)z0为f的奇点,则f在z0不可导. ()-|||-(4)f在点z0解析等价于f在z0的某个邻域内处处解析. ()-|||-(5)若f在闭区域D上处处解析,则存在包含D的区域B,使得f在B中处处-|||-解析. ()-|||-(6) (z)=u(x,y)+i(x,y) 在 _(1)=(x)_(0)+i(y)_(0) 连续等价于u(x,y ),v(x,y)在(x0,y0 )-|||-连续. ()-|||-(7) (x)=u(x,y)+i(x,y) 在点 _(0)=(x)_(0)+i(y)_(0) 可导等价于u(x,y ),v(x,y)在点-|||-(x0,y0)可微. ()-|||-(8) (x)=u(x,y)+i(x,y) 在点 _(0)=(x)_(0)+i(y)_(0) 解析等价于u(x,y),v(x,y)在点-|||-(x0,y0)可微且满足 Cauchy-Riemann 条件. ()-|||-(9) (x)=u(x,y)+i(x,y) 在点 _(0)=(x)_(0)+i(y)_(0) 解析等价于u(x,y),v(x,y)在点-|||-(x0,y0)的一个邻域内可微且满足 Cauchy-Riemann 条件. ()-|||-(10) |(sin )^2z|+|(cos )^2z|=1. ()-|||-(11) lim (e)^x=x ()