题目
合取证据“E1 AND E2”的可信度计算是？A. max(CF(E1), CF(E2))B. min(CF(E1), CF(E2))C. CF(E1) + CF(E2)D. CF(E1) × CF(E2)
合取证据“E1 AND E2”的可信度计算是？
A. max(CF(E1), CF(E2))
B. min(CF(E1), CF(E2))
C. CF(E1) + CF(E2)
D. CF(E1) × CF(E2)
题目解答
答案
B. min(CF(E1), CF(E2))
A. max(CF(E1), CF(E2))
B. min(CF(E1), CF(E2))
C. CF(E1) + CF(E2)
D. CF(E1) × CF(E2)