题目
单样本t检验的统计量计算公式为? A. t=(overline(x)-mu)/(S_(overline{x))=(overline(x)-mu_(0))/(S/sqrt(n)), v=n-1 overline(x)为样本均数, S为样本标准差, v为自由度 B. t=(overline(x)_(1)-overline(x)_(2))/(sqrt(S^2)((1)/(n_(1)+(1)/(n_{2)))), v=n_(1)+n_(2)-2 overline(x)_(1)、overline(x)_(2)分别表示两样本均数, S^2为合并方差 C. t=(overline(d)-mu_(d))/(S_(overline{d))=(overline(d)-0)/(S_(overline{d))/sqrt(n)}, v=n-1 overline(d)为样本均数, S_(overline{d)}为样本标准差, v为自由度 D. F=(max(S^2_(1),S^2_(2)))/(min(S^2)_(1,S^2_{2))}
单样本t检验的统计量计算公式为? A. $t=\frac{\overline{x}-\mu}{S_{\overline{x}}=\frac{\overline{x}-\mu_{0}}{S/\sqrt{n}}$, $v=n-1$ $\overline{x}$为样本均数, $S$为样本标准差, $v$为自由度 B. $t=\frac{\overline{x}_{1}-\overline{x}_{2}}{\sqrt{S^{2}(\frac{1}{n_{1}+\frac{1}{n_{2}})}}$, $v=n_{1}+n_{2}-2$ $\overline{x}_{1}$、$\overline{x}_{2}$分别表示两样本均数, $S^{2}$为合并方差 C. $t=\frac{\overline{d}-\mu_{d}}{S_{\overline{d}}=\frac{\overline{d}-0}{S_{\overline{d}}/\sqrt{n}}$, $v=n-1$ $\overline{d}$为样本均数, $S_{\overline{d}}$为样本标准差, $v$为自由度 D. $F=\frac{\max(S^{2}_{1},S^{2}_{2})}{\min(S^{2}_{1},S^{2}_{2})}$
题目解答
答案
A