题目
若Phi(0.5)=0.6915,Phi(1.5)=0.9332,Phi(2.5)=0.9938,设Xsim N(3,4),则X落在(-2, 2)内的概率为A. 0.0233B. 0.3023C. 0.3320D. 0.2302
若$\Phi(0.5)=0.6915$,$\Phi(1.5)=0.9332$,$\Phi(2.5)=0.9938$,设$X\sim N(3,4)$,则$X$落在(-2, 2)内的概率为
A. 0.0233
B. 0.3023
C. 0.3320
D. 0.2302
题目解答
答案
B. 0.3023