在山区飞行时应当注意,最强的乱流出现在:A. 山谷中间B. 山的迎风坡C. 山的背风坡

黄土和古土壤的测试指标中，指示东亚冬季风势力强弱的是（ ）。A. 粒度B. 磁化率C. 碳酸盐氧同位素组成D. 有机碳含量

升交点的赤径Ω,轨道的倾角 i ,确定了卫星轨道平面与地球体之间的相对定向。()A. 正确B. 错误

第一次课后作业答案:选择题: 1 B 2 C 3 D 5 D3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 105页参考答案4-1:b 4-2: c 4-4: a 4-5: a3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 不同温度的S值也可以直接用饱和水表查得。计算结果是0.3363-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 6-43-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 在总压101.33kPa、温度350.8K下,苯(1)-正己烷(2)形成x1=0.525的恒沸混合物。此温度下两组分的蒸汽压分别是99.4kPa和97.27kPa,液相活度系数模型选用Margules方程,气相服从理想气体,求350.8K下的气液平衡关系3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 和3-1-|||-.Delta n+dfrac (1)(2)(a)^2+g-Delta x=q- . △z=3m =m(2300-3230)-(10)^3-dfrac (1)(10)-dfrac (10)(3600) .q=0-|||-=2mdfrac ({E)_(1)}(s) dfrac ({10)^4cdot (m)_(B)}(3600s)=2mgdfrac ({E)_(8)}(s) =sqrt ({120)^2-(50)^2}=100sqrt (dfrac {1)(lg )} .-|||-Delta h=-2583times (10)^6J Delta a=109sqrt (dfrac {1)({b)_(8)}}-|||-.dfrac (1)(2)(m)^2=1.65times (10)^4dfrac (1)(s) cdot Delta (I)_(2)=erasure 1.729dfrac (J)(s)-|||-.+dfrac (1)(2)-(m)^2-gcdot L=-2567times (10)^6dfrac (1)(8) =(2567-(10)^6-dfrac (1)(8))=2567-(10)^6-erasure -|||-=dfrac (2583-2567)(2567)-100% 的函数式。

采用外加热重铬酸钾容量法测定土壤有机质含量时，需注意哪些问题？

读图，结合所学知识回答1～2题．80-|||-帮 70-|||-60-|||-H-|||-50-|||-→-|||-40° ★-|||-30-|||-20-|||-1990 1992 1994 1996 1998 2000 2002 2004年份-|||-甲 乙 丙 丁【小题1】正确反映我国城市化水平变化的曲线是（　　） A. 甲 B. 乙 C. 丙 D. 丁【小题2】在图示期间，与美国相比，我国（　　） A. 城市人口数较少 B. 城市人口数增长率较低 C. 城市人口比重较低 D. 城市人口比重增长率较低

正射影像特点:每个像素都具有(),逐像素纠正(看不到建筑物()面),可()。A. 经纬度坐标,立,三维浏览B. 三维坐标值,顶,量测C. 经纬度坐标,顶,测量D. 经纬度坐标,立,量测

2.根据图2完成以下填空。-|||-K-|||-C D-|||-D /0-|||-Z-|||-O-|||-e Z-|||-图2-|||-(1)标记为K( __ 纪)与其下岩层的接触关系为 __ o2.根据图2完成以下填空。-|||-K-|||-C D-|||-D /0-|||-Z-|||-O-|||-e Z-|||-图2-|||-(1)标记为K( __ 纪)与其下岩层的接触关系为 __ o2.根据图2完成以下填空。-|||-K-|||-C D-|||-D /0-|||-Z-|||-O-|||-e Z-|||-图2-|||-(1)标记为K( __ 纪)与其下岩层的接触关系为 __ o2.根据图2完成以下填空。-|||-K-|||-C D-|||-D /0-|||-Z-|||-O-|||-e Z-|||-图2-|||-(1)标记为K( __ 纪)与其下岩层的接触关系为 __ o2.根据图2完成以下填空。-|||-K-|||-C D-|||-D /0-|||-Z-|||-O-|||-e Z-|||-图2-|||-(1)标记为K( __ 纪)与其下岩层的接触关系为 __ o2.根据图2完成以下填空。-|||-K-|||-C D-|||-D /0-|||-Z-|||-O-|||-e Z-|||-图2-|||-(1)标记为K( __ 纪)与其下岩层的接触关系为 __ o

42.国家建立地图审核制度,向社会公开的所有地图-|||-均应当报送有审核权的测绘地理信息主管部门审-|||-核,方可向社会公布o-|||-A正确-|||-B错误