题目
3.0 10953.3466 100.0015 5 10Kg2.991010km。12m .S.PaKg(2)、TkG液相阻力只占总阻力的0.025/32 Y1为气膜控制，属于易溶气体0.4%1.33 107荷04%334.6624、1/22.4◎竺0.017532丫10.01751 Y10.01750.0178丫2丫(10.9)0.0178 0.10.00178丫1mX1X1Ylm________1.15V惰气量：22.4(10.0175)0.0155，X2= 0,kmol0.0439—S丫2mX20LmV(Y1血O.。439©01780.00178)0.0453X20.0155L0.0138丫1Y1X1________________________________0.0590.0120.0178 0.01380.001780.00274,0.0178 0.0138 In0.00178丫_上______5.85Ym0.00274气相传质单元数：25、上列平衡关系换算得Y=0.05，丫2=丫1(1-0.9)=0.0051V(122.4*kmol0.0476)°.°425可X2=0，X1V(Yi°.°384(由平衡线上丫1查得)________________丫2）LmX1X20.03840.05皿S________________V丫1丫2X1X2X1________________________________________1.5Lm______0龙砧1.5 0.05作图，（ 作线。（3）、从平衡线和操作线间在丫1=0.05，Y2=0.005范围内求得各Y及其对应当垂直距离Y-Y*。1）、根据题给Y、X数据作出平衡线。（2）、根据（Xi、Yi）、（X2、Y2）作出操（4）、Y对Y”2.94Y Y•••气相传质单元数为用解析法1.51_Y*作图，曲线下的面积,0.4060.306 0.2060.12250.10.444.52054.526、Lm101.3 1.50.015，丫2=0.015(1-0.98)=0.0003，X2=0________________0.013829SV" Y2)0.0138(0.015 0.0003)0.0103竺0SX1X20.015/0.76L=1.5x0.0103=0.0155kmol/S=0.28kg/SV(Y Y2)0.0138(0.015 0.0003)溶液出塔浓度:丫10.76X1X10.010L*丫20.01550.01310.76X20Ym丫1丫*,Y1丫1in丫2丫2________________________KyaA°Ym°.°15°.010°.00030.00167in。015°.0100.00030.0138(0.015 0.0003)20.10(0.785 0.8)0.001672.4mhG27、KyaAo________________hGaA01.6 146(0.785 1.52)Ky________________________aAoH YmV______00216皿22.4 3600 273 25.SXi0.0510.050.0526 Y20.002510.00250.0025*YiYm________1/180.0202（58为丙酮的mol质量）2X12 0.02020.0404 Y；0* *________________________________________________________________________In*丫1*丫2In________0.00250.00612/0.0216(0.0526 0.0025)KY2(0.9 93)(0.7850.82) 60.0061229、(1)、填料层增高3米后，因7.0104kmol. Ym2SV(Y丫2)0.0216(丫1丫2)92KyaA。Ym0.0007(0.9 93)(0.785 0.8)Ym整理得丫m0.0815（Y1丫2）L(2)、求丫2L 0.0536 2.48V0.0216平衡关系：Y=2.0X*2V(Y1丫2)0.0216(0.0526 0.0025)X10.02020.0536X1VL(Y1丫2）1肃°.°526丫2),X2=0丫12X1(0.0526丫2)0.04240.807%2.48丫1”丫20.0815(Y1Y2),丫1丫1In丫2[0.0526 (0.04240.807%)]丫2Ym0.0815(£丫2)|n______O0815^05260.0102 0.193Y.,0.012 0.807Y2In丫2(3)、求丙酮回收率0.00429 0.0815Y2，用试探法求丫2•••出口气体含丙酮0.1%丫_^20.°526°.°0198.1%¥0.0526与原条件相比：(¥Y2)/Y0.0526 0.001,cc121.03
3.0 10953.3466 100.0015 5 10Kg2.991010km。12m .S.PaKg(2)、TkG液相阻力只占总阻力的0.025/32 Y1为气膜控制，属于易溶气体0.4%1.33 107荷04%334.6624、1/22.4◎竺0.017532丫10.01751 Y10.01750.0178丫2丫(10.9)0.0178 0.10.00178丫1mX1X1Ylm________1.15V惰气量：22.4(10.0175)0.0155，X2= 0,kmol0.0439—S丫2mX20LmV(Y1血O.。439©01780.00178)0.0453X20.0155L0.0138丫1Y1X1________________________________0.0590.0120.0178 0.01380.001780.00274,0.0178 0.0138 In0.00178丫_上______5.85Ym0.00274气相传质单元数：25、上列平衡关系换算得Y=0.05，丫2=丫1(1-0.9)=0.0051V(122.4*kmol0.0476)°.°425可X2=0，X1V(Yi°.°384(由平衡线上丫1查得)________________丫2）LmX1X20.03840.05皿S________________V丫1丫2X1X2X1________________________________________1.5Lm______0龙砧1.5 0.05作图，（ 作线。（3）、从平衡线和操作线间在丫1=0.05，Y2=0.005范围内求得各Y及其对应当垂直距离Y-Y*。1）、根据题给Y、X数据作出平衡线。（2）、根据（Xi、Yi）、（X2、Y2）作出操（4）、Y对Y”2.94Y Y•••气相传质单元数为用解析法1.51_Y*作图，曲线下的面积,0.4060.306 0.2060.12250.10.444.52054.526、Lm101.3 1.50.015，丫2=0.015(1-0.98)=0.0003，X2=0________________0.013829SV" Y2)0.0138(0.015 0.0003)0.0103竺0SX1X20.015/0.76L=1.5x0.0103=0.0155kmol/S=0.28kg/SV(Y Y2)0.0138(0.015 0.0003)溶液出塔浓度:丫10.76X1X10.010L*丫20.01550.01310.76X20Ym丫1丫*,Y1丫1in丫2丫2________________________KyaA°Ym°.°15°.010°.00030.00167in。015°.0100.00030.0138(0.015 0.0003)20.10(0.785 0.8)0.001672.4mhG27、KyaAo________________hGaA01.6 146(0.785 1.52)Ky________________________aAoH YmV______00216皿22.4 3600 273 25.SXi0.0510.050.0526 Y20.002510.00250.0025*YiYm________1/180.0202（58为丙酮的mol质量）2X12 0.02020.0404 Y；0* *________________________________________________________________________In*丫1*丫2In________0.00250.00612/0.0216(0.0526 0.0025)KY2(0.9 93)(0.7850.82) 60.0061229、(1)、填料层增高3米后，因7.0104kmol. Ym2SV(Y丫2)0.0216(丫1丫2)92KyaA。Ym0.0007(0.9 93)(0.785 0.8)Ym整理得丫m0.0815（Y1丫2）L(2)、求丫2L 0.0536 2.48V0.0216平衡关系：Y=2.0X*2V(Y1丫2)0.0216(0.0526 0.0025)X10.02020.0536X1VL(Y1丫2）1肃°.°526丫2),X2=0丫12X1(0.0526丫2)0.04240.807%2.48丫1”丫20.0815(Y1Y2),丫1丫1In丫2[0.0526 (0.04240.807%)]丫2Ym0.0815(£丫2)|n______O0815^05260.0102 0.193Y.,0.012 0.807Y2In丫2(3)、求丙酮回收率0.00429 0.0815Y2，用试探法求丫2•••出口气体含丙酮0.1%丫_^20.°526°.°0198.1%¥0.0526与原条件相比：(¥Y2)/Y0.0526 0.001,cc121.03
题目解答
答案
0.0178 V" Y2)0.0439(0.0178 0.00178)O.°178O.。0178 0.0425(0.050.005) 1.5Lm V(Yi丫2) 0.0425(0.050.005) kmol 0.4 V(Y Y2) kmol.丫 V(YiY>) 2000(10.05)273 0.065/58 丫1¥ 丫2丫2 0.0526 0.04040.0025 0.0526 0.0404 0.0526 (0.0424 0.80") Y Y2 0.0309 0.021 % 0.004 0.0006 0.012 0.0294