由q线方程;=dfrac (q)(q-1)x-dfrac ({x)_(r)}(q-1)-|||-__知:(1.5分)=dfrac (q)(q-1)x-dfrac ({x)_(r)}(q-1)-|||-__,得:=dfrac (q)(q-1)x-dfrac ({x)_(r)}(q-1)-|||-__,得q=1.55(1.5分)(2)求馏出液组成xD,原料液组成xF,①由精馏段操作线方程得:=dfrac (q)(q-1)x-dfrac ({x)_(r)}(q-1)-|||-__,=dfrac (q)(q-1)x-dfrac ({x)_(r)}(q-1)-|||-__(1.5分)②由q线方程得:=dfrac (q)(q-1)x-dfrac ({x)_(r)}(q-1)-|||-__,=dfrac (q)(q-1)x-dfrac ({x)_(r)}(q-1)-|||-__(1.5分)(3)若R’=3,精馏段x2=0.82,y3=0.86,求xD’由精馏段操作线方程得:=dfrac (q)(q-1)x-dfrac ({x)_(r)}(q-1)-|||-__,代入已知量:=dfrac (q)(q-1)x-dfrac ({x)_(r)}(q-1)-|||-__=dfrac (q)(q-1)x-dfrac ({x)_(r)}(q-1)-|||-__,得=dfrac (q)(q-1)x-dfrac ({x)_(r)}(q-1)-|||-__(2分)在连续精馏塔中分离两组分理想溶液。已知原料液组成为0.6(摩尔分数,下同),馏出液组成为0.9,釜残液组成为0.02。泡点进料。(1)求每获得1kmol/h馏出液时的原料液用量F;(2)若回流比为1.5,它相当于最小回流比的多少倍?(3)假设原料液加到加料板上后,该板的液相组成仍为0.6,求上升到加料板上的气相组成。(物系的平均相对挥发度为3)