因为ca?,g?h1b1?h2b2?h3b3 ?,cb??h1h3h2h3?gh1h2h3??利用ai?bj?2??ij,容易证明?gh1h2h3?????ca?0?????cb?0????所以,倒格子矢量g?h1b1?h2b2?h3b3垂直于密勒指数为(h1h2h3)的晶面系。1.6、对于简单立方晶格,证明密勒指数为(h,k,l)的晶面系,面间距d满足:d?a其中a为立方边长;并说明面指数简单的晶面,其面密度较大,容易解理。?????????