题目

螯合物萃取体系的萃取常数K_({ex)}与螯合物的分配系数K_(D({MA)_n)}、螯合剂的分配系数K_(D({HA))}、螯合剂的解离常数K_(a({HA))}和螯合物的稳定常数beta_(n({MA)_n)}之间的关系式为（）A. K_({ex)} = K_(D({MA)_n)} cdot beta_(n({MA)_n)} cdot (K_(D({HA))})/(K_(a({HA)))}B. K_({ex)} = K_(D({MA)_n)} cdot beta_(n({MA)_n)} cdot ((K_(a({HA))})/(K_(D({HA)))})^n

螯合物萃取体系的萃取常数$K_{\text{ex}}$与螯合物的分配系数$K_{D(\text{MA}_n)}$、螯合剂的分配系数$K_{D(\text{HA})}$、螯合剂的解离常数$K_{a(\text{HA})}$和螯合物的稳定常数$\beta_{n(\text{MA}_n)}$之间的关系式为（）

A. $K_{\text{ex}} = K_{D(\text{MA}_n)} \cdot \beta_{n(\text{MA}_n)} \cdot \frac{K_{D(\text{HA})}}{K_{a(\text{HA})}}$

B. $K_{\text{ex}} = K_{D(\text{MA}_n)} \cdot \beta_{n(\text{MA}_n)} \cdot \left(\frac{K_{a(\text{HA})}}{K_{D(\text{HA})}}\right)^n$

题目解答

答案

B. $K_{\text{ex}} = K_{D(\text{MA}_n)} \cdot \beta_{n(\text{MA}_n)} \cdot \left(\frac{K_{a(\text{HA})}}{K_{D(\text{HA})}}\right)^n$