题目6、行星轮机构中轮O固定,半径-|||-为R,轮A的半径为r,连杆OA铰接-|||-在两轮的中心,其角速度为w,方-|||-向如图所示,问轮A的转动角速度-|||-wA等于多少?-|||-A r-|||-(omega )_(A)=dfrac (R+r)(r)omega w-|||-、-|||-R-|||-bigcirc (1)A=CD-|||-(omega )_(A)=dfrac (r)(R)-|||-(omega )_(A)=dfrac (r)(R+r)omega 题目解答答案