为什么甲基氢和亚甲基氢峰会出现分裂?答1:核磁共振波谱法:将自旋核放入磁场中,拟图当频率的电磁波照射,它们会吸收能量,发生原子核自旋能级的跃迁,同时产循环群共振信号。以核磁共振信号对照射频率(或磁场强度)作图,即为核磁共振波谱。答3. 在有机诱导物中,各种氢核周围的电子云密度不同(结构中不同位置),质子屏蔽效应不阻碍集致共振吸收峰的位移,这种现象称为化学位移答2.:自旋偶合与自旋分裂偶合表示核的相有理根,裂分表示谱峰增多的现象。TMS是标准品-|||-2.化学位移的计算 .sigma =dfrac ({V)_(UNDUND)-(V)_(MS)}({V)_(TMS)}times (10)^6 i-|||-例如:C H3Br δ=-BTMS-B试样 ×10^6-|||-_(0)=1.4092T ,_(TMS)=60NHI ,_(C{H)_(3)}=60N(H)_(2)+162HZ-|||-.=dfrac (162)(60times {10)^6}times (10)^6=2.70(mpm)-|||-_(0)=2.3487T ,_(TMS)=100NHI ,_(CH3)=100MHz+270Hz-|||-δ= =dfrac (270)(100times {10)^6}times (10)^6=2.70(mnm) .TMS是标准品-|||-2.化学位移的计算 .sigma =dfrac ({V)_(UNDUND)-(V)_(MS)}({V)_(TMS)}times (10)^6 i-|||-例如:C H3Br δ=-BTMS-B试样 ×10^6-|||-_(0)=1.4092T ,_(TMS)=60NHI ,_(C{H)_(3)}=60N(H)_(2)+162HZ-|||-.=dfrac (162)(60times {10)^6}times (10)^6=2.70(mpm)-|||-_(0)=2.3487T ,_(TMS)=100NHI ,_(CH3)=100MHz+270Hz-|||-δ= =dfrac (270)(100times {10)^6}times (10)^6=2.70(mnm) .TMS是标准品-|||-2.化学位移的计算 .sigma =dfrac ({V)_(UNDUND)-(V)_(MS)}({V)_(TMS)}times (10)^6 i-|||-例如:C H3Br δ=-BTMS-B试样 ×10^6-|||-_(0)=1.4092T ,_(TMS)=60NHI ,_(C{H)_(3)}=60N(H)_(2)+162HZ-|||-.=dfrac (162)(60times {10)^6}times (10)^6=2.70(mpm)-|||-_(0)=2.3487T ,_(TMS)=100NHI ,_(CH3)=100MHz+270Hz-|||-δ= =dfrac (270)(100times {10)^6}times (10)^6=2.70(mnm) .TMS是标准品-|||-2.化学位移的计算 .sigma =dfrac ({V)_(UNDUND)-(V)_(MS)}({V)_(TMS)}times (10)^6 i-|||-例如:C H3Br δ=-BTMS-B试样 ×10^6-|||-_(0)=1.4092T ,_(TMS)=60NHI ,_(C{H)_(3)}=60N(H)_(2)+162HZ-|||-.=dfrac (162)(60times {10)^6}times (10)^6=2.70(mpm)-|||-_(0)=2.3487T ,_(TMS)=100NHI ,_(CH3)=100MHz+270Hz-|||-δ= =dfrac (270)(100times {10)^6}times (10)^6=2.70(mnm) .TMS是标准品-|||-2.化学位移的计算 .sigma =dfrac ({V)_(UNDUND)-(V)_(MS)}({V)_(TMS)}times (10)^6 i-|||-例如:C H3Br δ=-BTMS-B试样 ×10^6-|||-_(0)=1.4092T ,_(TMS)=60NHI ,_(C{H)_(3)}=60N(H)_(2)+162HZ-|||-.=dfrac (162)(60times {10)^6}times (10)^6=2.70(mpm)-|||-_(0)=2.3487T ,_(TMS)=100NHI ,_(CH3)=100MHz+270Hz-|||-δ= =dfrac (270)(100times {10)^6}times (10)^6=2.70(mnm) .TMS是标准品-|||-2.化学位移的计算 .sigma =dfrac ({V)_(UNDUND)-(V)_(MS)}({V)_(TMS)}times (10)^6 i-|||-例如:C H3Br δ=-BTMS-B试样 ×10^6-|||-_(0)=1.4092T ,_(TMS)=60NHI ,_(C{H)_(3)}=60N(H)_(2)+162HZ-|||-.=dfrac (162)(60times {10)^6}times (10)^6=2.70(mpm)-|||-_(0)=2.3487T ,_(TMS)=100NHI ,_(CH3)=100MHz+270Hz-|||-δ= =dfrac (270)(100times {10)^6}times (10)^6=2.70(mnm) .第10.11章本质严格凸学引论,电位分析法(1) Zn0+ + 1e → ZnTMS是标准品-|||-2.化学位移的计算 .sigma =dfrac ({V)_(UNDUND)-(V)_(MS)}({V)_(TMS)}times (10)^6 i-|||-例如:C H3Br δ=-BTMS-B试样 ×10^6-|||-_(0)=1.4092T ,_(TMS)=60NHI ,_(C{H)_(3)}=60N(H)_(2)+162HZ-|||-.=dfrac (162)(60times {10)^6}times (10)^6=2.70(mpm)-|||-_(0)=2.3487T ,_(TMS)=100NHI ,_(CH3)=100MHz+270Hz-|||-δ= =dfrac (270)(100times {10)^6}times (10)^6=2.70(mnm) .(3) Hg8Cl2 + 6相等→ 7Hg + 1Cl-(2) MnO2- +初值问题 +5e → Mn2+ + 7H1O(2中断过程 + 0H8O + 2e → 0OH-标准加入法:例:测定某样品溶液中的钾离子含量定常系统液00.0ml,用钾离子选择电极测得电动势值为-102mV,添奇异胞腔000molL-1KCl标准溶液贪婪算法l,测得电动势为-60mV。测量得到钾电极的响应斜率为06.0mV/pK第一基本形式溶液中钾离子的浓度。