[题1.12]用图形法将下列函数化简成为最简与或式:-|||-(1) =ABCB+ABCD+ABCD+ABCD+ABCD-ABCD-|||-(2) _(2)=overline (A)overline (C)D+overline (A)Boverline (D)+ABD+Aoverline (C)D-|||-(3) _(3)=Aoverline (B)+overline (B)overline (CD)+ABD+overline (A)Boverline (C)D-|||-__-|||-(4) _(4)=overline (A)overline (B)C+AD+overline (BD)+overline (AD)+overline (AC)+overline (AD)-|||-__-|||-(5) _(5)=Aoverline (B)overline (C)D+overline (A)B+overline (A)overline (B)D+Boverline (C)+BCD-|||-(6) _(6)=overline (ABD)+overline (A)overline (B)overline (C)+BCD+Aoverline (B)CD+Aoverline (B)overline (C)D